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Цены на электромонтажные работы в Ялте: прайс-лист 2020 г.

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90000 How to Find The Suitable Size of Cable & Wire? 90001 90002 90003 How to Determine the Proper Size of Wire & Cable for Electrical Wiring Installation? 90004 90005 90006 90007 Voltage Drop in Cables 90008 90009 90010 We know that all conductors and cables (except super conductor) have some amount of resistance. 90011 90010 This resistance is directly proportional to the length and inversely proportional to the diameter of conductor i.e. 90011 90010 90003 R α L / a 90004 … [Laws of resistance R = ρ (L / a)] 90011 90010 Whenever current flows through a conductor, a voltage drop occurs in that conductor.Generally, voltage drop may neglect for small length of conductors but in case of a lower diameter and long length conductors, we have to take into account the considerable voltage drops for proper wiring installation and future load managment. 90011 90010 According to 90003 IEEE rule B-23 90004, at any point between power supply terminal and installation, 90003 Voltage drop should not increase above 2.5% of the provided (supply) voltage 90004. 90011 90010 90027 90027 90011 90030 90003 Example: 90004 90033 90010 if the Supply voltage is 220V AC, then the value of allowable voltage drop should be; 90011 90036 90037 90003 Allowable Voltage Drop 90004 = 220 x (2.5/100) = 90003 5.5V 90004 90042 90043 90010 In electrical wiring circuits, voltage drops also occur from the distribution board to the different sub circuit and final sub circuits, but for sub circuits and final sub circuits, the value of voltage drop should be half of that allowable voltage drops (ie 2.75V of 5.5V as calculated above) 90011 90010 Normally, Voltage drop in tables is described in 90003 Ampere per meter (A / m) 90004 eg what would be the voltage drop in a one meter cable which carrying one Ampere current? 90011 90010 There are two methods to define the 90003 voltage drop in a cable 90004 which we will discuses below.90011 90010 In 90003 SI 90004 (90003 System international and metric system 90004) voltage drop is described by 90003 ampere per meter (A / m) 90004. 90011 90010 In 90003 FPS (foot pound system) 90004 voltage drop is described in length based which is 90003 100 feet. 90004 90011 90036 90037 90007 Update 90008: Now you may also use the following electrical Calculators to find 90003 Voltage drop & the wire size in American wire gauge 90004 system. 90042 90043 90076 90037 90003 Electrical Wire & Cable Size Calculator (Copper & Aluminum) 90004 90042 90037 90003 Wire & Cable Size Calculator in AWG 90004 90042 90037 90003 Voltage Drop in Wire & Cable Calculator 90004 90042 90089 90006 90007 Tables & Charts for Proper Cable & Wire Sizes 90092 90008 90009 90010 Below are the important Tables which you should follow for determining the proper size of cable for Electrical Wiring Installation.90011 90010 90098 Click image to enlarge 90099 90092 90101 90101 90011 90010 90098 Click image to enlarge 90099 90011 90010 90109 90109 Click image to enlarge 90011 90010 90113 90113 90011 90010 90098 Click image to enlarge 90099 90011 90010 90121 90121 90098 Click image to enlarge 90099 90011 90010 90127 90127 90011 90006 90003 How to Find the Voltage Drop in a Cable? 90004 90009 90010 90007 To find voltage drop in a cable, follow the simple steps given below.90008 90011 90036 90037 First of all, find the maximum allowable voltage drop 90042 90037 Now, Find load current 90042 90037 Now, according to load current, select a proper cable (which current rating should be nearest to the calculated load current) from table 1 90042 90037 From Table 1, find the voltage drop in meter or 100 feet (what system you prefer) according its rated current 90042 90043 90010 (Stay cool 🙂 we will follow both methods and system for finding voltage drops (in meter and 100 feet ) in our solved example for whole electrical installation wiring).90011 90036 90037 Now, calculate the voltage drop for the actual length of wiring circuit according to its rated current with the help of 90098 90003 following formulas 90004 90099. 90042 90043 90010 (Actual length of circuit x volt drop for 1m) / 100 -> to find Volt drop in per meter. 90092 (Actual length of circuit x volt drop for 100ft) / 100> to find volt drop in 100 feet. 90011 90036 90037 Now multiply this calculated value of volt drop by load factor where; 90042 90043 90010 Load factor = Load Current to be taken by Cable / Rated Current of Cable given in the table.90011 90036 90037 This is the value of Volt drop in the cables when load current flow through it. 90042 90037 If the calculated value of voltage drop is less than the value calculated in step (1) (Maximum allowable voltage drop), than the size of selected cable is proper 90042 90037 If the calculated value of voltage drop is greater than the value calculated in step (1) (Maximum allowable voltage drop), than calculate voltage drop for the next (greater in size) cable and so on until the calculated value of voltage drop became less than the maximum allowable voltage drop calculated in step (1).90042 90043 90010 Related Posts: 90011 90006 90003 How to Determine the Proper Cable & Wire Size for Given Load? 90004 90009 90030 90007 Below are solved examples showing how to find the proper Cable Size for Given Load. 90008 90033 90010 For a given load, cable size may be found with the help of different tables but we should keep in mind and follow the rules about voltage drop. 90011 90010 Determining the size of cable for a given load, take into account the following rules. 90011 90010 For a given load except the known value of current, there should be 20% extra scope of current for additional, future or emergency needs.90011 90010 From Energy meter to Distribution board, Voltage drop should be 90003 1.25% 90004 and for final sub circuit, voltage drop should not exceed 90003 2.5% 90004 of Supply voltage. 90011 90010 Consider the change in temperature, when needed, use temperature factor (Table 3) 90011 90010 Also, consider the load factor when finding the size of cable 90011 90010 When determining the cable size, consider the wiring system i.e. in open wiring system, temperature would be low but in conduit wiring, temperature increases due to the absence of air.90011 90010 Related Posts: 90011 90006 90007 Solved Examples of Proper Wire & Cable Size 90092 90008 90009 90010 Following are the examples of determining the proper Size of cables for electrical wiring installation which will make it easy to understand the method of «how to determine the proper size of cable for a given load «. 90011 90030 90007 Example 1 ……. 90214 (British / English System) 90215 90008 90033 90010 For Electrical wiring installation in a building, Total load is 4.5kW and total length of cable from energy meter to sub circuit distribution board is 35 feet. Supply voltages are 220V and temperature is 40 ° C (104 ° F). Find the most suitable size of cable from energy meter to sub circuit if wiring is installed in conduits. 90011 90010 90007 Solution: — 90008 90011 90036 90037 Total Load = 4.5kW = 4.5 x1000W = 90003 4500W 90004 90042 90037 20% additional load = 4500 x (20/100) = 90003 900W 90004 90042 90037 Total Load = 4500W + 900W = 90003 5400W 90004 90042 90037 Total Current = I = P / V = ​​5400W / 220V = 90003 24.5A 90004 90042 90043 90010 Now select the size of cable for load current of 90003 24.5A 90004 (from Table 1) which is 7 / 0.036 (28 Amperes) it means we can use 7 / 0.036 cable according table 1. 90011 90010 Now check the selected (7 / 0.036) cable with temperature factor in Table 3, so the temperature factor is 0.94 (in table 3) at 40 ° C (104 ° F) and current carrying capacity of (7 / 0.036) is 28A, therefore, current carrying capacity of this cable at 40 ° C (104 ° F) would be; 90011 90010 90003 Current rating for 40 ° C (104 ° F) = 28 x 0.94 = 26.32 Amp. 90004 90011 90010 Since the calculated value (90003 26.32 Amp 90004) at 90003 40 ° C 90004 (90003 104 ° F 90004) is less than that of current carrying capacity of (7 / 0.036) cable which is 90003 28A 90004, therefore this size of cable (90003 7 / 0.036 90004) is also suitable with respect to temperature. 90011 90010 Now find the voltage drop for 100 feet for this (7 / 0.036) cable from 90003 Table 4 90004 which is 90003 7V 90004, But in our case, the length of cable is 35 feet.Therefore, the voltage drop for 35 feet cable would be; 90011 90010 Actual Voltage drop for 35 feet = (7 x 35/100) x (24.5 / 28) = 90003 2.1V 90004 90011 90010 And Allowable voltage drop = (2.5 x 220) / 100 = 90003 5.5V 90004 90011 90010 Here The Actual Voltage Drop (2.1V) is less than that of maximum allowable voltage drop of 5.5V. Therefore, the appropriate and most suitable cable size is (7 / 0.036) for that given load for Electrical Wiring Installation. 90011 90030 90007 Example 2 ……. (SI / Metric / Decimal System) 90008 90033 90010 What type and size of cable suits for given situation 90011 90010 Load = 5.8kW 90011 90010 Volts = 230V AV 90011 90010 Length of Circuit = 35 meter 90011 90010 Temperature = 35 ° C (95 ° F) 90011 90010 90007 Solution: — 90008 90011 90010 Load = 5.8kW = 5800W 90011 90010 90003 Voltage 90004 = 90003 230V 90004 90011 90010 90003 Current 90004 = I = P / V = ​​5800/230 = 90003 25.2A 90004 90011 90010 90003 20% additional load current 90004 = (20/100) x 5.2A = 90003 5A 90004 90011 90010 90003 Total Load Current = 25.2A + 5A = 30.2A 90004 90011 90010 Now select the size of cable for load current of 30.2A (from Table 1) which is 7 / 1.04 (31 Amperes) it means we can use 7 / 0.036 cable according 90003 table 1 90004. 90011 90010 Now check the selected (7 / 1.04) cable with temperature factor in Table 3, so the temperature factor is 0.97 (in table 3) at 35 ° C (95 ° F) and current carrying capacity of (7 / 1.04) is 31A, therefore, current carrying capacity of this cable at 40 ° C (104 ° F) would be; 90011 90010 90003 Current rating for 35 ° C (95 ° F) = 31 x 0.97 = 30 Amp. 90004 90011 90010 Since the calculated value (30 Amp) at 35 ° C (95 ° F) is less than that of current carrying capacity of (7/1.04) cable which is 31A, therefore this size of cable (7 / 1.04) is also suitable with respect to temperature. 90011 90010 Now find the voltage drop for per ampere meter for this (7 / 1.04) cable from (Table 5) which is 7mV, But in our case, the length of cable is 35 meter. Therefore, the voltage drop for 35 meter cable would be: 90011 90010 90003 Actual Voltage drop for 35meter 90004 = 90011 90010 90003 = mV x I x L 90004 90011 90010 (7/1000) x 30 × 35 = 90003 7.6V 90004 90011 90010 And 90003 Allowable voltage drop 90004 = (2.5 x 230) / 100 = 90003 5.75V 90004 90011 90010 Here the actual Voltage drop (7.35V) is greater than that of maximum allowable voltage drop of 5.75V. Therefore, this is not suitable size of cable for that given load. So we will select the next size of selected cable (7 / 1.04) which is 7 / 1.35 and find the voltage drop again. According to Table (5) the current rating of 7 / 1.35 is 40Amperes and the voltage drop in per ampere meter is 4.1 mV (See table (5)). Therefore, the actual voltage drop for 35 meter cable would be; 90011 90010 Actual Voltage drop for 35 meter = 90011 90010 90098 90003 = mV x I x L 90004 90099 90011 90010 (4.1/1000) x 40 × 35 = 7.35V = 90003 5.74V 90004 90011 90010 This drop is less than that of maximum allowable voltage drop. So this is the 90003 most appropriate and suitable cable or wire size 90004. 90011 90030 90007 Example 3 90008 90033 90010 Following Loads are connected in a building: — 90011 90010 90003 90214 Sub-Circuit 1 90215 90004 90011 90036 90037 2 lamps each o 1000W and 90042 90037 4 fans each of 80W 90042 90037 2 TV each of 120W 90042 90043 90010 90003 90214 Sub-Circuit 2 90215 90004 90011 90036 90037 6 Lamps each of 80W and 90042 90037 5 sockets each of 100W 90042 90037 4 lamps each of 800W 90042 90043 90010 If supply voltages are 230 V AC, then 90003 calculate circuit current 90004 and 90003 Cable size for each Sub-Circuit 90004? 90011 90010 90007 Solution: — 90008 90011 90010 90003 Total load of Sub-Circuit 1 90004 90011 90010 = (2 x 1000) + (4 x 80) + (2 × 120) 90011 90010 = 2000W + 320W + 240W = 2560W 90011 90010 Current for Sub-Circuit 1 = I = P / V = ​​2560/230 = 90003 11.1A 90004 90011 90010 90003 Total load of Sub-Circuit 2 90004 90011 90010 = (6 x 80) + (5 x 100) + (4 x 800) 90011 90010 = 480W + 500W + 3200W = 90003 4180W 90004 90011 90010 Current for Sub -Circuit 2 = I = P / V = ​​4180/230 = 90003 18.1A 90004 90011 90010 Therefore, 90098 90003 Cable suggested for sub circuit 1 90004 90099 = 90003 3 / .029 90004 «(90003 13 Amp 90004) or 90003 1 / 1.38 mm 90004 (90003 13 Amp 90004) 90011 90010 90003 90098 Cable suggested for Sub-Circuit 2 90099 90004 = 90003 7 /.029 90004 «(90003 21 Amp 90004) or 90003 7 / 0.85 mm (24 Amp) 90004 90011 90010 Total Current drawn by both Sub-Circuits = 11.1A + 18.1A = 90003 29.27 A 90004 90011 90010 So 90003 90098 cable suggested for Main -Circuit 90099 90004 = 90003 7 / .044 «(34 Amp) 90004 or 90003 7 / 1.04 mm (31 Amp 90004) 90011 90030 90007 Example 4 90008 90033 90010 A 10H.P (7.46kW) three phase squirrel cage induction motor of continuous rating using Star-Delta starting is connected through 400V supply by three single core PVC cables run in conduit from 250feet (76.2m) away from multi-way distribution fuse board. Its full load current is 19A. Average summer temperature in Electrical installation wiring is 35 ° C (95 ° F). Calculate the size of the cable for motor? 90011 90010 90007 Solution: — 90008 90011 90036 90037 90003 Motor load 90004 = 10H.P = 10 x 746 = 7460W 90003 * (1H.P = 746W) 90004 90042 90037 90003 Supply Voltage 90004 = 400V (3-Phase) 90042 90037 90003 Length of cable 90004 = 250feet (76.2m) 90042 90037 90003 Motor full load Current 90004 = 19A 90042 90037 90003 Temperature factor 90004 for 35 ° C (95 ° F) = 0.97 (From Table 3) 90042 90043 90010 Now select the size of cable for full load motor current of 19A (from Table 4) which is 7 / 0.36 «(23 Amperes) * (Remember that this is a 3-phase system ie 3 -core cable) and the voltage drop is 5.3V for 100 Feet. It means we can use 7 / 0.036 cable according Table (4). 90011 90010 Now check the selected (7 / 0.036) cable with temperature factor in table (3), so the temperature factor is 0.97 (in table 3) at 35 ° C (95 ° F) and current carrying capacity of (7 / 0.036 «) is 23 Amperes, therefore, current carrying capacity of this cable at 40 ° C (104 ° F) would be: 90011 90010 90098 90003 Current rating for 40 ° C (104 ° F) = 23 x 0.97 = 22.31 Amp. 90004 90099 90011 90010 Since the calculated value (22.31 Amp) at 35 ° C (95 ° F) is less than that of current carrying capacity of (7 / 0.036) cable which is 23A, therefore this size of cable (7 / 0.036) is also suitable with respect to temperature. 90011 90010 90003 Load factor = 19/23 = 0.826 90004 90011 90010 Now find the voltage drop for 100feet for this (7 / 0.036) cable from table (4) which is 5.3V, But in our case, the length of cable is 250 feet. Therefore, the voltage drop for 250 feet cable would be; 90011 90010 90003 Actual Voltage drop 90004 for 250feet = (5.3 x 250/100) x 0.826 = 90003 10.94V 90004 90011 90010 And maximum 90003 Allowable voltage drop 90004 = (2.5 / 100) x 400V = 90003 10V 90004 90011 90010 Here the actual Voltage drop (10.94V) is greater than that of maximum allowable voltage drop of 10V. Therefore, this is not suitable size of cable for that given load. So we will select the next size of selected cable (7 / 0.036) which is 7 / 0.044 and find the voltage drop again. According to Table (4) the current rating of 7 / 0.044 is 28 Amperes and the volt drop in per 100 feet is 4.1V (see Table 4). Therefore, the actual voltage drop for 250 feet cable would be; 90011 90010 Actual Voltage drop for 250 feet = 90011 90010 = 90003 Volt drop per 100 feet x length of cable x load factor 90004 90011 90010 (4.1 / 100) x 250 x 0.826 = 90003 8.46V 90004 90011 90010 And Maximum Allowable voltage drop = (2.5 / 100) x 400V = 90003 10V 90004 90011 90010 The actual voltage drop is less than that of maximum allowable voltage drop. So this is the most appropriate and suitable cable size for Electrical wiring Installation of given situation.90011 90010 Related Posts: 90011.90000 Automatic UPS / Inverter Wiring & Connection Diagram to the Home 90001 90002 90003 Automatic UPS System Wiring Circuit Diagram (One Live Wire & Ordinary Wiring) 90004 90005 90006 90007 90003 Automatic UPS / Inverter Connections 90005 90010 90011 In case of emergency breakdown when utility power is not available from the power house, we may use automatic inverter / UPS and batteries to connect the power without interruption. 90012 90011 We will show two basic UPS / Inverter with batteries connection the home distribution board.90012 90015 90016 Auto UPS / Inverter with Two Wires 90017 90016 Automatic USP / Inverter Wiring with One Live Wire 90017 90020 90011 Note: To be in safe mode, use 90003 6 AWG 90005 (90003 7/064 «90005 or 90003 16mm 90027 2 90028 90005) cable and wire size to 90003 connect the UPS to the main panel board 90005. 90012 90033 90003 Automatic UPS / Inverter Wiring with two Wires. 90005 90036 90011 No rocket science here. Just connect the outgoing Neutral and Live wires to the UPS. Now connect the two outgoing Neutral and Phase wires from UPS / Inverter (As output) to the appliances as shown in fig 1.90012 90011 90040 90040 90012 90033 90003 UPS / Inverter Wiring with Single Additional Live Wire 90005 90036 90011 As a basic, we know that each load points should be connected through Live (Phase) and Neutral wire to operate normally. In case below, we have already connected the Phase & Neutral (from Power house to the utility pole & Distribution board then) to each electrical appliance i.e. Fans, Light points etc.That’s what we do in our distribution board for home wiring. 90004 90012 90011 Now, according to the below UPS connection diagram, connect an extra wire (Phase) to those appliances where we have already connected Phase and Neutral wires from (Power house & DB) (i.e., two wire as phase (Live) as shown in the below fig). And no need to connect extra Neutral wire from UPS as it is already installed & connected before. In simple words, You only need a live wire to connect to the appliances as shown in fig 2. Now the quieten arise here «Why extra Phase wire and not a Neutral? … Yes .. Read the following working and operation of the circuit to get the idea. 90004 90012 90011 You may also read: 90012 90011 Click image to enlarge 90012 90057 90057 Automatic UPS Inverter System Wiring Diagram (One Live Wire) 90007 90003 Working and Operation of UPS Connection 90004 90005 90010 90011 90065 (1) When utility power is not available from power house 90066 90012 90011 In this case, electric supply will continue through Phase wire (Output of UPS) which is connected to the batteries and UPS and then to electrical appliances (Note that Neutral is already connected).So the first one phase wire which has already connected before UPS installation (i.e. Live Wire from Main board to UPS) would be inactive because power supply is not available from power house. In this case, connected electrical appliances through the live wire from UPS / Inverter consume the stored electrical energy in the batteries without interruption. 90012 90011 Related Tutorials: 90012 90011 90065 (2) When power supply restores from power grid 90004 90066 90012 90011 Then power supply will continue through the Phase wire (Note that Neutral is already connected) which is connected to the UPS from main board (it will charge your battery as well) and then from UPS to connected electrical appliances.So the second one (phase or live wire) which is connected after UPS installation (i.e. One Live Wire from UPS) would be inactive because power supply is not available from UPS and batteries (Because it is Automatic UPS System). 90012 90007 90065 How to Connect a UPS / Inverter to the Switch Board? 90066 90004 90065 90084 90066 90010 90011 The below fig 3 shows that how to connect a UPS / Inverter with batteries to the Main Distribution Unit for continues power supply in case of the utility power failure.90012 90011 Additional wiring connection with connected load and appliances for two rooms in home. How to Connect Automatic UPS / Inverter to the Home Supply System? 90004 90012 90011 Click image to enlarge 90012 90094 90094 How to connect UPS / inverter to the distribution board? 90011 90003 Wiring Color Code: 90005 90012 90011 We have used 90003 Red 90005 for 90003 Live 90005 or 90003 Phase 90005, 90003 Black 90005 for 90003 Neutral 90005 and 90003 Green 90005 for Earth Wire in single phase.You may use the specific area codes i.e. 90003 IEC — International Electrotechnical Commission 90005 (UK, EU etc) or 90003 NEC (National Electrical Code 90005 [US & Canada] where; 90012 90011 90003 NEC: 90005 90012 90011 90123 90003 Single Phase 120V AC: 90005 90126 90012 90011 90003 Black 90005 = 90003 Phase 90005 or 90003 Line 90005, 90003 White 90005 = 90003 Neutral 90005 and 90003 Green 90005/90003 Yellow 90005 = 90003 Earth Conductor 90005 90012 90011 90003 IEC: 90005 90012 90011 90123 90003 Single Phase 230V AC: 90005 90126 90012 90011 90003 Brown 90005 = 90003 Phase 90005 or 90003 Line 90005, 90003 Blue 90005 = 90003 Neutral 90005 and 90003 Green 90005 = 90003 Earth Conductor.90005 90012 90011 90084 90003 General Precautions while playing with Electricity. 90005 90012 90015 90016 Disconnect the power source before servicing, repairing or installing electrical equipments. 90017 90016 Use the proper cable in size with this simple calculation method (How to determine the suitable size of cable for Electrical Wiring Installation) 90017 90016 Never try to work on electricity without proper guidance and care. 90017 90016 Work with electricity only in presence of those persons who has good knowledge and practical work and experience who know how to deal with electricity.90017 90016 Read all the instructions, user manuals, cautions and follow them strictly. 90017 90016 Doing your own electrical work is dangerous as well as illegal in some areas.Contact the licensed electrician or the power supply company before practicing any change in electrical wiring connection. 90017 90016 The author will not be liable for any losses, injuries, or damages from the display or use of this information or if you try any circuit in wrong format. So please! Be careful because it’s all about electricity and electricity is too dangerous.90017 90020 90011 Related Posts: 90012 90011 Now If you still facing difficulties or do not understand the wiring diagram, do not hesitate to leave a comment or just check the other related step by step tutorials about UPS / Inverter Wiring Diagrams & Connections with description, and operation. 90012 90011 You may also read other Electrical Wiring Installation Tutorials. 90012.90000 Electrical Cable / Wire Sizing — Electrical Engineering Centre 90001 90002 This time i want shared about 90003 how to sizing the electrical cable 90004 .This topic is important because it’s involved with safety issue, cost and time line for the electrical installation project. 90005 90002 Cable or wire sizing matter already discussed for a long time ago and it’s a hot topic for Electricians and Engineers.So i hope from this post, it can give a clear view and understanding how to select current rating for wire, cable rating, voltage drop, and wire sizing for wiring project application 90005 90002.From cable / wire sizing calculation we can estimate the proper size for cable to our wiring installation project.One thing that we need to prepared before cable or wire sizing is several data or information about wiring project includes: 90005 90010 How to sizing the electrical cable / wire? 90011 90002 1) Type of load: For feeder, control panel, distribution board (DB) or motor 90005 90002 2) Power Source: AC / DC power for Three phase or single phase 90005 90002 3) Full load current (Ampere) 90005 90002 4) Circuit Breaker size 90005 90002 5) Types of cable (PVC, XLPE, Fire proved) 90005 90002 6) Installation Condition (Underground, trefoil, trunking, tray or conduit) 90005 90002 7) Distance / length of cable run from source to load 90005 90002 90005 90010 Calculation for sizing electrical cable / wire 90011 90030 Ib ≤ In ≤ Iz 90031 90002 Ib = Amperage load 90005 90002 In = Circuit Breaker size 90005 90002 Iz = Current rating for cable / wire 90005 90002 90005 90002 90003 Example: 90004 90005 90002 We plan to install 1 unit induction motor 75 hp for running a water pump.Power factor value is 0.8 and motor efficiency is 0.85.Power supply for this motor is 415 volt 3 phase 50Hz.Distance from panel to motor is 75 meter.This panel and pump is located at outside of factory.Please sizing the suitable circuit breaker, electrical cable and also type of cable for this application. 90005 90002 90003 Calculation 90004 90005 90030 Ib ≤ In ≤ Iz 90031 90002 Ib = (hp x 746) / (√3 x Volt x PF x Efficiency) 90005 90002 Ib = (75 x 746) / (√3 x 415 x 0.8 x 0.85) 90005 90002 90003 Ib = 114.5 Ampere 90004 90005 90002 90005 90002 In = Ib ≤ breaker sizing 90005 90002 In = 114 ≤ 150 ampere 90005 90002 90003 In = 150 ampere 90004 (we decide to used MCCB 3 pole with 150 ampere rating) 90005 90002 90005 90002 Iz = In ≤ Iz 90005 90002 Iz = 150 ≤ Iz 90005 90002 90003 Iz = 187 ampere (carried capacity for 50mm² cable size) 90004 90005 90002 So we decide to used cable size = 50 mm² with 4 core cable and clipped direct to cable tray.To confirm this cable size, we need to calculate the voltage drop.90005 90002 90083 90005 90002 * For full table of cable size, please download cable size chart / table below.Clink link to download PDF file for Cable Current Rating Table 90005 90030 90031 90002 90010 Voltage Drop Calculation 90011 90005 90002 Below is a voltage drop calculation that i made for cable power supply from panel to induction motor. 90005 90002 From Panel to Induction motor = 75 meter 90005 90002 mV = 0.87 (refer table below) 90005 90099 90030 90031 90030 Formula voltage drop: Vd = Ib x length (meter) x mV / 1000 90031 90002 Vd = (114.5 x 75 x 0.87) / 1000 90005 90002 Vd = 7.47 (Acceptable refer to IEE 17th edition) 90005 90002 * Voltage drop acceptable value is 4% x 415 volt = 16.6 Volt 90005 90002 90003 Conclusion 90004 90005 90002 From this calculation, we fully confident to laying cable size 90003 50mm² 90004 with 90003 150 ampere 90004 of MCCB, using 90003 multicore PVC Armored cable 90004 (due to outdoor wiring application) and also cable laying with cable tray. 90005 90002 That why all Electrician and Electrical Engineer need to know about cable sizing calculation to make sure wiring installation project successful and meet the requirement of Electrical Safety and Regulation without any disaster.90005 .90000 Rated characteristics of Electrical Contactors 90001 90002 90003 Rated characteristics of Contactors 90004 90005 90006 90007 90003 Types: 90004 90010 90011 90012 90007 Electromagnetic 90010 90007 Electro-pneumatic 90010 90007 Pneumatic 90010 90019 90020 Related Post: Important Terms and Definitions related to Motor Control and Protection 90021 90022 90007 90003 Interrupting Medium: 90004 90010 90011 90020 90029 90029 90021 90020 Related Post: Abnormal Operating Condition and Causes of Induction Motors 90021 90034 90007 90003 Rated values ​​of voltages: 90004 90010 90011 90012 90007 90003 Rated voltage (Operational voltage) 90043 90004 For a three phase contactors, the voltage between phases is called rated voltage or operational voltage.90010 90007 90003 Rated Insulation Voltage 90004 The voltage, on which performs the dielectric test. 90010 90019 90020 Related Post: The Star-Delta (Y-Δ) 3-phase Motor Starting Method by Automatic star-delta starter with Timer. 90021 90053 90007 90003 Rated Values ​​of Current: 90004 90010 90011 90012 90007 90003 Rated Thermal Current 90004: The maximum current, on which a Contactor operates continuously for eight (8) hours without increasing the temperature (increased with a permissible limit).90010 90007 90003 Rated Operational Current: 90004 A Manufacturer tells the rated operational current considering Contactor’s rated frequency, operational voltages, rated duty and utilization factor. 90010 90019 90020 Related Post: Main Difference between Contactor and Starter. 90021 90071 90007 90003 Rated duty and Serves Conditions: 90004 90010 90011 90012 90007 90003 Eight Hours Duty 90004: A Contactor can carry the normal current for more than 8 hours. The contactor’s rated thermal current can be found by 8 hours duty.90010 90007 90003 Uninterrupted duty 90004: A Contactor can be close for a long time (from 8 hours to many years) without interruption. However, Due to Oxidation and dust on contacts, Temperature may be increased. 90010 90007 90003 Contactor’s making Capacity 90004: Contactor’s rated making capacity is the value of current, on which the contacts of contactor can make the connections (i.e. Contactor can close their contacts) without arcing or melting. A.C contactor’s making capacity is defined according to the Current Symmetrical Component’s R.M.S value. 90010 90007 90003 Contactor’s Breaking Capacity 90004: Contactor’s rated breaking capacity is the value of current, on which the contacts of contactor can break the connections (i.e. Contactor can open their contacts) without arcing or melting. A.C contactor’s breaking capacity is defined according to the Current R.M.S value. 90010 90019 90020 Related Posts: 90021.